In ∆abc , Lb= 90 and tanA = 1/√3 . Find sinA cosC + cosA since

 

Asked by Dhruv | 5th Jul, 2021, 04:12: PM

Expert Answer:

It is assumed that ( sinA cosC + cosA sinC ) is required to find.
 
( sinA cosC + cosA sinC ) = sin(A+C) = sin(180 - B ) = sinB
 
If given angle begin mathsize 14px style angle end styleB = 90o , then 
sin(A+C) = sin(180 - B ) = sinB = sin90 = 1

Answered by Thiyagarajan K | 18th Sep, 2021, 12:27: PM