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# CBSE Class 10 Answered

In ∆abc , Lb= 90 and tanA = 1/√3 . Find sinA cosC + cosA since

Asked by Dhruv | 05 Jul, 2021, 04:12: PM Expert Answer
It is assumed that ( sinA cosC + cosA sinC ) is required to find.

( sinA cosC + cosA sinC ) = sin(A+C) = sin(180 - B ) = sinB

If given angle B = 90o , then
sin(A+C) = sin(180 - B ) = sinB = sin90 = 1
Answered by Thiyagarajan K | 18 Sep, 2021, 12:27: PM

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