In a triangle ABC, AB = 6, BC = 8 and AC = 10. A perpendicular from B meets the side AC at D. A circle is drawn with radius BD and centre B. If the circle cuts AB and BC respectively at P and Q, then AP : QC is equal to

 

Asked by keshavendu35 | 23rd Aug, 2018, 10:47: PM

Expert Answer:

begin mathsize 16px style Area space of space increment ABC equals 1 half cross times 6 cross times 8 equals 24 space sq. space units
area space of space increment ABD equals 1 half cross times 10 cross times BD equals 24
BD equals 4.8
AP equals 6 minus 4.8 equals 1.2
QC equals 8 minus 4.8 equals 3.2
fraction numerator begin display style AP end style over denominator QC end fraction equals fraction numerator 1.2 over denominator 3.2 end fraction equals 3 over 8





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Answered by Sneha shidid | 24th Aug, 2018, 11:18: AM