In a hydraulic machine a force of 0.6N acts normally on a smaller piston of area 0.2 square metre. The force that acts on the larger piston whose area ia 200 sq m will be-
a) 60gf
b)60 kg wt
c)600kgf
d)60 N
Asked by adityaahuja099 | 16th Oct, 2017, 01:39: PM
Expert Answer:
Pressure = Force / Area
pressure under smaller piston 
Force on 200 sq.m area piston is = 3 x 200 = 600 N = 60 kg wt
Answered by | 16th Oct, 2017, 04:30: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change