In a hydraulic machine a force of 0.6N acts normally on a smaller piston of area 0.2 square metre. The force that acts on the larger piston whose area ia 200 sq m will be-
a) 60gf
b)60 kg wt
c)600kgf
d)60 N
Asked by adityaahuja099
| 16th Oct, 2017,
01:39: PM
Expert Answer:
Pressure = Force / Area
pressure under smaller piston 
Force on 200 sq.m area piston is = 3 x 200 = 600 N = 60 kg wt
Answered by
| 16th Oct, 2017,
04:30: PM
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