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ifa piece of iron gains 10 percent of its weight due to partial rusting into fe2o3 then what is the percentage of total iron rusted
Asked by tiwariakanksha0103 | 24 Jul, 2019, 19:46: PM
Expert Answer
The chemical reaction for rusting of iron is as follows:
4Fe + 3O2 → 2Fe2O3
Initial mass of iron =100 gm
Mass of Fe2O3 = 110 gm
Mass of oxide = 10 gm
Now, from equation,
To form 2 moles of rust it requires 3 moles of O2 requires 4 moles of Fe
10/32 moles will use
Mass of Fe reacted = 0.4166×56
=23.33%
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