ICSE Class 7 Answered
If the distance travelled by the body is given by 2s=10t+2t^2 then the find acceleration the body is?
Asked by ramesh.gaganchapa | 09 Oct, 2019, 17:27: PM
The distance travelled is,
2s = 10 t + 2t2 ... (1)
We know, the second equation of motion is given as,
![s space equals space u t plus space 1 half a t squared](https://images.topperlearning.com/topper/tinymce/cache/89d280124210c791e01bc42ba5a4a913.png)
Thus, equation (1) can be written as,
![s space equals space fraction numerator 10 t over denominator 2 end fraction plus 1 half left parenthesis 2 right parenthesis space t squared space space space... left parenthesis 3 right parenthesis](https://images.topperlearning.com/topper/tinymce/cache/00c86734bc3ea62a8344e8ab78206c2d.png)
Comparing equation (2) and (3), we get,
acceleration, a = 2 m/s2
Answered by Shiwani Sawant | 10 Oct, 2019, 12:50: PM
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