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CBSE Class 10 Answered

If p(x) = x^2 + ax + b such that p(x) = 0 and p(p(p(x))) = 0 have equal root then find the integral value of p(0).p(1).
Asked by acv27joy | 14 Dec, 2018, 02:46: PM
answered-by-expert Expert Answer

p(x) = x2 + ax + b

p(x)=0

And p(p(p(x)))=0

p(p(0))=0

p(b)=0

b2 + ab + b = 0

b(b + a + 1) = 0

b = 0   or  b + a + 1 = 0

We get p(0) = b and p(1) = 1 + a + b

Find p(0) × p(1) we get p(0) × p(1) = 0

Answered by Sneha shidid | 17 Dec, 2018, 10:42: AM

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