CBSE Class 10 Answered
If p(x) = x^2 + ax + b such that p(x) = 0 and p(p(p(x))) = 0 have equal root then find the integral value of p(0).p(1).
Asked by acv27joy | 14 Dec, 2018, 02:46: PM
Expert Answer
p(x) = x2 + ax + b
p(x)=0
And p(p(p(x)))=0
p(p(0))=0
p(b)=0
b2 + ab + b = 0
b(b + a + 1) = 0
b = 0 or b + a + 1 = 0
We get p(0) = b and p(1) = 1 + a + b
Find p(0) × p(1) we get p(0) × p(1) = 0
Answered by Sneha shidid | 17 Dec, 2018, 10:42: AM
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