CBSE Class 10 Answered
if one zero of the polynomial is (a²+9) x²+13x+6a is reciprocal of the other ,find the value of a
Asked by sharmaraushan079 | 19 Aug, 2022, 16:04: PM
Expert Answer
Let t and 1/t be the roots of (a2 + 9) x2 + 13x + 6a.
Product of the roots = t x 1/t = (constant term)/(coefficient of x2)
⇒ (6a) / (a2 + 9) = t x 1/t
⇒ (6a) / (a2 + 9) = 1
⇒ a2 - 6a + 9 = 0
⇒ (a - 3)2 = 0
⇒ a - 3 = 0
⇒ a = 3
Therefore, the value of a is 3
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