if one zero of 2x²-5x+lambda is 3/2, then find the value of lambda and other zero

Asked by s.kmounesha | 23rd May, 2022, 02:35: PM

Expert Answer:

Since, one of the zeroes is 3/2.
rightwards double arrow 2 open parentheses 3 over 2 close parentheses squared minus 5 open parentheses 3 over 2 close parentheses plus straight lambda equals 0
rightwards double arrow 2 cross times 9 over 4 minus 5 cross times 3 over 2 plus straight lambda equals 0
rightwards double arrow 9 over 2 minus 15 over 2 plus straight lambda equals 0
rightwards double arrow straight lambda equals fraction numerator 15 minus 9 over denominator 2 end fraction equals 3
The space equation space becomes
2 straight x squared minus 5 straight x plus 3 equals 0
2 straight x squared minus 2 straight x minus plus 3 straight x plus 3 equals 0
2 straight x left parenthesis straight x minus 1 right parenthesis minus 3 left parenthesis straight x minus 1 right parenthesis equals 0
left parenthesis straight x minus 1 right parenthesis left parenthesis 2 straight x minus 3 right parenthesis equals 0
straight x equals 1 space and space straight x equals 3 over 2

Answered by Renu Varma | 27th May, 2022, 11:30: AM