ICSE Class 10 Answered
if (k-3),(2k+1) and (4k+3) are three consecutive terms of an arthmetic progression,find the value of k
Asked by t.singireddy | 10 Nov, 2019, 15:21: PM
(k-3),(2k+1) and (4k+3) are three consecutive terms of an arithmetic progression.
Hence,
(2k + 1) - (k - 3) = (4k + 3) - (2k + 1)
k + 4 = 2k + 2
k = 2
Answered by Renu Varma | 10 Nov, 2019, 19:50: PM
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