IF IN 6 TRIALS OF AN EXPERIMENT THE PROBABILITY OF 2 SUCCESS IS 9 TIME THE PROBABILITY OF 4 SUCCESS THEN FIND THE PROBABILITY OF SUCCESS IN ONE TRIAL? HOW TO DO THIS. PLZ HELP

Asked by Akhil Mohan | 6th Jan, 2013, 03:54: PM

Expert Answer:

let the probability of success =x
      probability of failure=1-x
    probability of 2 success=6c2(x^2)(1-x)^4
   probability of 4 success=6c4(x^4)(1-x)^2
 according to question
                            6c2(x^2)(1-x)^4=9*(6c4)(x^4)(1-x)^2
                           6c2(1-x)^2=9*6c2(x^2)
                               1+x^2-2x=9x^2
                       8x^2+2x-1=0
   solving x=-1/2
          or x=1/4
 so probability of success=1/4

Answered by  | 6th Jan, 2013, 10:45: PM

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