IF IN 6 TRIALS OF AN EXPERIMENT THE PROBABILITY OF 2 SUCCESS IS 9 TIME THE PROBABILITY OF 4 SUCCESS THEN FIND THE PROBABILITY OF SUCCESS IN ONE TRIAL? HOW TO DO THIS. PLZ HELP
Asked by Akhil Mohan
| 6th Jan, 2013,
03:54: PM
Expert Answer:
let the probability of success =x
probability of failure=1-x
probability of 2 success=6c2(x^2)(1-x)^4
probability of 4 success=6c4(x^4)(1-x)^2
according to question
6c2(x^2)(1-x)^4=9*(6c4)(x^4)(1-x)^2
6c2(1-x)^2=9*6c2(x^2)
1+x^2-2x=9x^2
8x^2+2x-1=0
solving x=-1/2
or x=1/4
so probability of success=1/4
Answered by
| 6th Jan, 2013,
10:45: PM
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