IF IN 6 TRIALS OF AN EXPERIMENT THE PROBABILITY OF 2 SUCCESS IS 9 TIME THE PROBABILITY OF 4 SUCCESS THEN FIND THE PROBABILITY OF SUCCESS IN ONE TRIAL? HOW TO DO THIS. PLZ HELP

let the probability of success =x

      probability of failure=1-x

    probability of 2 success=6c2(x^2)(1-x)^4

   probability of 4 success=6c4(x^4)(1-x)^2

 according to question

                            6c2(x^2)(1-x)^4=9*(6c4)(x^4)(1-x)^2

                           6c2(1-x)^2=9*6c2(x^2)

                               1+x^2-2x=9x^2

                       8x^2+2x-1=0

   solving x=-1/2

          or x=1/4

 so probability of success=1/4