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If alpha and Beta are the zeroes  of the polynomial  x^2-p(x+1)-c,  find the value of (alpha +1)(beta+1)
Asked by Nimmi | 07 May, 2019, 11:36: PM Expert Answer
If alpha and Beta are the zeroes  of the polynomial  x^2-p(x+1)-c,  find the value of (alpha +1)(beta+1)

x2 - p(x + 1) - c
x2 - px - p - c

Comparing with ax2 + bx + c, we get
a= 1 , b = -p and c = - p - c

α and β are the zeroes of the given polynomial.

→ α + β = -b/a = -(-p)/1 = p

and αβ = c/a = -p - c / 1 = -p - c

To find: (α + 1)(β + 1)
(α + 1)(β + 1) = αβα + β + 1
= - p - c + p + 1
= 1 - c
Answered by Yasmeen Khan | 08 May, 2019, 10:52: AM

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