CBSE Class 10 Answered
If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1)
Asked by Nimmi | 07 May, 2019, 11:36: PM
Expert Answer
If alpha and Beta are the zeroes of the polynomial x^2-p(x+1)-c, find the value of (alpha +1)(beta+1)
x2 - p(x + 1) - c
= x2 - px - p - c
Comparing with ax2 + bx + c, we get
a= 1 , b = -p and c = - p - c
α and β are the zeroes of the given polynomial.
→ α + β = -b/a = -(-p)/1 = p
and αβ = c/a = -p - c / 1 = -p - c
To find: (α + 1)(β + 1)
(α + 1)(β + 1) = αβ + α + β + 1
= - p - c + p + 1
= 1 - c
Answered by Yasmeen Khan | 08 May, 2019, 10:52: AM
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