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CBSE Class 10 Answered

If alpha and beta are the zeroes of the polynomial p(x)=6×x×x+x-2,find 1÷alpha+1÷beta-alpha×beta
Asked by tominmathai10 | 14 May, 2019, 08:24: AM
answered-by-expert Expert Answer
begin mathsize 16px style straight p left parenthesis straight x right parenthesis space equals space 6 straight x squared space plus space straight x space minus space 2 space Here space straight a space equals space 6 comma space straight b space equals space 1 space and space straight c space equals space minus 2 To space find colon 1 over straight alpha space space plus space 1 over straight beta space minus space αβ space equals space fraction numerator straight alpha space plus space straight beta over denominator αβ end fraction space minus space αβ space equals space fraction numerator space straight alpha space plus space straight beta space minus space open parentheses αβ close parentheses squared over denominator αβ end fraction straight alpha space plus space straight beta space equals space fraction numerator negative straight b over denominator straight a end fraction space equals space fraction numerator negative 1 over denominator 6 end fraction space and space αβ space equals space straight c over straight a equals fraction numerator negative 2 over denominator 6 end fraction space equals space fraction numerator negative 1 over denominator 3 end fraction rightwards double arrow space fraction numerator space straight alpha space plus space straight beta space minus space open parentheses αβ close parentheses squared over denominator αβ end fraction space equals space fraction numerator fraction numerator negative 1 over denominator 6 end fraction space minus open parentheses fraction numerator negative 1 over denominator 3 end fraction close parentheses squared space over denominator fraction numerator negative 1 over denominator 3 end fraction end fraction equals space fraction numerator fraction numerator negative 1 over denominator 6 end fraction minus 1 over 9 over denominator fraction numerator negative 1 over denominator 3 end fraction end fraction equals fraction numerator negative 3 space minus space 2 over denominator 18 end fraction divided by space fraction numerator negative 1 over denominator 3 end fraction space equals space 5 over 18 cross times space 3 equals space 5 over 6 end style
Answered by Yasmeen Khan | 14 May, 2019, 09:29: AM

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