CBSE Class 12-science Answered
how to find the logarithmic differentiation of logx raised to the power x?
Asked by bharathmazumdar | 23 May, 2013, 07:12: PM
Expert Answer
y = (logx)^x
logy = xlog(logx)
Differentiating both sides
1/y *y' = log(logx) + x*1/logx * 1/x
y' = (logx)^x [log(logx) + 1/logx]
Answered by | 24 May, 2013, 01:44: AM
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