how to find the logarithmic differentiation of logx raised to the power x?

Asked by bharathmazumdar | 23rd May, 2013, 07:12: PM

Expert Answer:

y = (logx)^x
logy = xlog(logx)
Differentiating both sides
1/y *y' = log(logx) + x*1/logx * 1/x
y' = (logx)^x [log(logx) + 1/logx]

Answered by  | 24th May, 2013, 01:44: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.