Request a call back

# Maharashtra Class 10 Answered

How much time would a satellite in an orbit at a height of 35780 km above the earths surface take to complete one revolution around the earth, if the mass of the earth were four times it's original mass?
Asked by Annonymous4210 | 09 Feb, 2020, 11:39: AM
When a Satellite is orbiting around earth with orbital radius R, centripetal force is same as gravitational attraction force

Hence we have,    mv2/R  = GMm/R2 ..................(1)

where m is mass of satellite, v is speed of satellite, G is gravitational constant and M is mass of earth

Let T is period of revolution . By using the substitution v = 2πR/T  in eqn.(1) and after simplification we get,

T 1/√M

[ Orbital radius R is kept constant ]

Hence if mass of earth has increased 4 times , time period will decrease to half of initial value

Answered by Thiyagarajan K | 09 Feb, 2020, 02:00: PM

## Concept Videos

Maharashtra 10 - Physics
Asked by 16msas0711 | 29 May, 2023, 11:13: AM
Maharashtra 10 - Physics
Asked by vedantwaje8 | 29 Sep, 2022, 10:00: AM
Maharashtra 10 - Physics
Asked by hiyajain001 | 29 Dec, 2021, 09:40: AM
Maharashtra 10 - Physics
Asked by dilippaithane749 | 12 Feb, 2021, 09:50: PM
Maharashtra 10 - Physics
Asked by vedhikanaik2004 | 23 Dec, 2020, 09:07: PM
Maharashtra 10 - Physics
Asked by Tejalkothari3427 | 06 Sep, 2020, 09:38: AM