Maharashtra Class 10 Answered
How much time would a satellite in an orbit at a height of 35780 km above the earths surface take to complete one revolution around the earth, if the mass of the earth were four times it's original mass?
Asked by Annonymous4210 | 09 Feb, 2020, 11:39: AM
Expert Answer
When a Satellite is orbiting around earth with orbital radius R, centripetal force is same as gravitational attraction force
Hence we have, mv2/R = GMm/R2 ..................(1)
where m is mass of satellite, v is speed of satellite, G is gravitational constant and M is mass of earth
Let T is period of revolution . By using the substitution v = 2πR/T in eqn.(1) and after simplification we get,
T 
1/√M
1/√M [ Orbital radius R is kept constant ]
Hence if mass of earth has increased 4 times , time period will decrease to half of initial value
Answered by Thiyagarajan K | 09 Feb, 2020, 02:00: PM
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