CBSE Class 9 Answered
how far should a man go from the centre of the earth such that his wieght is 1/4th that on the earth?radius of the earth=6400km.
Asked by SHERIL SINGH | 15 Sep, 2010, 01:51: PM
Expert Answer
The weight of the man = mg.
Value of g = GM/(R*R), where G is gravitational constant
M is mass of earth and R is radius of the earth.
Hence, to be weight equal to 1/4
g' = g/4
This means
GM/(R'*R') = (1/4)GM/(R*R)
This means
R'=2*R
Hence the R' = 2* 6400
= 12800 km
Hence the man should go at a distance of 12800 km from the earth in order to reduce his weight to 1/4.
Regards,
Answered by | 15 Sep, 2010, 02:51: PM
Application Videos
Concept Videos
CBSE 9 - Physics
Asked by mailtoparvathyprajith | 08 Feb, 2024, 12:13: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by harshsrivastava8896606 | 17 Apr, 2023, 01:47: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sknv159357 | 05 Jan, 2023, 08:29: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by advscjaglan | 09 Aug, 2022, 08:22: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by munendramishra478 | 12 Jul, 2022, 08:42: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sumantk60559 | 10 Jun, 2022, 07:18: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by rk7213908 | 31 Mar, 2022, 12:28: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by rk7213908 | 21 Feb, 2022, 04:48: PM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by mannatjohn920 | 15 Feb, 2022, 09:57: AM
ANSWERED BY EXPERT
CBSE 9 - Physics
Asked by sudiptaroy0607 | 08 Jan, 2022, 04:59: PM
ANSWERED BY EXPERT