How can we prove that when an object is thrown up and it comes down, the time of ascent is equal to the time of descent?

Asked by PP Methuku | 18th Sep, 2012, 09:09: PM

Expert Answer:

Let the initial velocity of throwing be u
thus time taken to reach the toppest point be T
thus using the first equation of motion:
T = u/g
distance travelled:
H = uT - 1/2gT2
H = 1/2u2/g
 
now when the ball coms down, the time taken to travel H distance:
u2/(2g) = 1/2gt2
thus t = u/g
hence proved

Answered by  | 18th Sep, 2012, 09:42: PM

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