Request a call back

Hi..tick the correct option
(12) when a body is projcted vertically upwards, its height h as a function of time t is given by, h =ut-(1/2)gt2 ,
where u is initial speed, g is acceleration due to gravity. h(t) is a quadratic function in time t,
vertical distance travelled per given interval of time keep on decreasing.

Hence graph(C) shows the variation of height with respect to time t

(13) when an object is moving without any external force, its speed is constant.
Hence graph(B) shows the constant speed with respect to time t

(14) when a body is pulled by a horizontal net force, if force is constant, then it is subjected to uniform acceleration a .
Displacemnt S for this movemenr of this body, S = (1/2)at2 , a quadratic function in time t.
Distance moved in equal interval of time keep on increasing. Hence graph(D) shows this kind of motion
Answered by Thiyagarajan K | 02 May, 2019, 09:35: AM

## Concept Videos

CBSE 12-science - Physics
Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
CBSE 12-science - Physics
CBSE 12-science - Physics
Asked by mishrigupta19319 | 07 Apr, 2024, 11:23: AM
CBSE 12-science - Physics
CBSE 12-science - Physics
Asked by amlanmcob | 06 Apr, 2024, 12:27: PM
CBSE 12-science - Physics
Asked by hussain221man | 05 Apr, 2024, 08:44: PM