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CBSE Class 10 Answered

Geometrical derive the value of sin zero
Asked by amolshukal.2001 | 31 Jan, 2018, 08:53: AM
answered-by-expert Expert Answer
begin mathsize 16px style Let space angle BAC equals straight theta space be space an space acute space angle space and space straight B space be space straight a space point space on space its space terminal space side space straight A l.
Draw space perpendicular space BC space from space straight B space on space AC.
In space increment ACB comma
sinθ equals BC over AB space comma space cosθ equals AC over AB space and space tanθ equals BC over AC
It space is space evident space from space increment ACB space that space has space straight theta space becomes space smaller space and space smaller comma
line space BC space becomes space smaller space and space smaller space and space finally space when space straight theta space becomes space 0 degree
point space straight B space will space coincide space with space straight C. space Consequently comma
BC equals 0 space and space AB equals AC
sin 0 degree equals BC over AB equals 0
similarly space find space remaining space ratios space of space 0 degree.
From space increment ACB comma
It space is space evident space that space straight theta space increase space line space segment space AC space becomes space smaller space and space smaller
finally space straight theta space becomes space 90 degree space point space straight C space will space coincide space with space straight A.
AC equals 0 comma space AB equals BC
sin 90 degree equals BC over AB equals space AB over AB equals 1
Similarly space find space remaining space ratios space of space 90 degree end style
Answered by Sneha shidid | 31 Jan, 2018, 10:21: AM
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