g.b
Asked by PRAMOD
| 7th Dec, 2013,
05:50: PM
Expert Answer:
The given A.P is 121, 117, 113…
Here, first term a = 121 and common difference, d = –4.
Let nth term be the first negative term of the given A.P
∴ an < 0
121 + (n – 1) (–4) < 0 (an = a + (n – 1) d)
–4n + 125 < 0
– 4n < – 125
n > 31.25
∴ n = 32 [Since n is a natural number]
Thus, 32nd term is the first negative term of the given A.P.
∴ n = 32 [Since n is a natural number]
Thus, 32nd term is the first negative term of the given A.P.
Answered by
| 7th Dec, 2013,
07:07: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change