From the given velocity time graph, calculate : (i) deacceleration in region AB (ii) accleration in region BC (iii) total distance travelled in the region ABC (iv) average velocity between 10 s and 30 s ?
Asked by nisha_vini29 | 9th Jul, 2017, 11:34: PM
The following steps need to be taken for finding each quantity:
Step 1) For region AB, the deceleration will be found by the slope of line AB. Take the end points in order to find the slope. It will be negative and you will get the deceleration.
Step 2) Acceleration in region BC will be the slope of the line BC.
Step 3) The distance covered in the region ABC is the area under the curve. So, find the area of the trapeziums AFEB and BEDC. Add both these to get the distance covered.
Step 4) Average velocity is given as the ratio of the distance travelled to the time taken. So, divide the area under the curve obtained in step 3 by the time difference 30 s - 10 s = 20 s to get the average velocity.
Answered by Romal Bhansali | 10th Jul, 2017, 10:30: AM
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