CBSE Class 12-science Answered
For which position of the object magnification of convex lens is minus one
Asked by rakeshgowda51088 | 01 Mar, 2019, 08:53: PM
Expert Answer
magnification (v/u) = -1 , where v is lens-to-image distance and u is lens-to object distance.
hence we get v = -u
if we substitute v = - u in lens equation (1/v)-(1/u) = (1/f), we get -(1/u) - (1/u) = 1/f or u = -2f
hence if object is placed at a distance 2f, we get magnification of image -1
Answered by Thiyagarajan K | 01 Mar, 2019, 10:04: PM
Concept Videos
-
Electric Charge - Part 1
This video describes the concept of charge, conductors and insulators, and ... -
Gold Leaf Electroscope - Part 1
This video explains the basic properties of electric charges. -
Coulom's Law of Electric Force - Part 1 ...
This video describes Coulomb's law to calculate the force between any two p... -
All about electric fields
Define electric field in terms of Coulomb's force. Apply superposition prin... -
Electric Field Lines
This video explains the representation of electric field due to a single ch...
CBSE 12-science - Physics
Asked by ankush76728 | 06 May, 2024, 04:52: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by ankush76728 | 05 May, 2024, 09:55: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by heymindurownbusiness | 04 May, 2024, 11:15: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by talulu | 01 May, 2024, 05:14: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by kanishkg511 | 30 Apr, 2024, 07:25: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by sahoobanita89 | 30 Apr, 2024, 05:10: AM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by divakar.9124 | 27 Apr, 2024, 10:42: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by panneer1766 | 24 Apr, 2024, 01:52: PM
ANSWERED BY EXPERTCBSE 12-science - Physics
Asked by artabandhusahu85 | 24 Apr, 2024, 12:07: PM
ANSWERED BY EXPERT
