For complex numbers according to the closure law of multiplication the product two of complex numbers is a complex number. but when we multiple the following two complex numbers...
which is a real number.
thus this proves the closure law to be incorrect. please explain.
Asked by Rida Mukadam | 5th Jun, 2015, 06:52: PM
Every real number is a complex number with imaginary part as '0'.
The number '2' can be written as '2 + 0i'
The set of real numbers is a subset of set of complex numbers. Hence, the closure law of multiplication is still valid even if the result is a real number.
Answered by satyajit samal | 6th Jun, 2015, 08:56: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number