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following cell has emf 0.7995V.Pt|(atm)|HNO3(1M)||AgNO3(1M)|AG.IF WE AFF ENOUGH KCl TO THE Agcell so the final Cl_is 1M .Now the measured emf of the cell is 0.222V.The Ksp of Agcl
Asked by meenakshiswyd | 21 May, 2020, 22:07: PM
answered-by-expert Expert Answer
We are unable to understand this question. Kindly post the full question either by correctly typing or by attaching an image of question with it. We will help you to clear your doubt. 
Answered by Ramandeep | 22 May, 2020, 20:55: PM

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