CBSE Class 12-science Answered
First q
Asked by jain.pradeep | 01 Sep, 2019, 23:46: PM
Expert Answer
Figure shows the action of different forces. WA and WB are the weight or gravitational forces of sphere-A and sphere-B respectively.
N1A and N1B are Normal forces provided by the inclined plane on spheres as shown in figure.
N2A is the Normal force provided by the inclined plane that is making angle 20° with vertical
By resolving the components of WA and WB , we get ,
N1A = WA cos20 = 3000×cos20 = 2819 N ................................(1)
N1B = WB cos20 = 9000×cos20 = 8457 N ..............................(2)
Force acting against the inclined plane that is inclined with vertical by 20º is
sum of ( WAsin20 ) and ( WBsin20 ) as shown in figure as F = ( WA sin20 ) + ( WB sin20 )
Hence the componet of F along the normal force N2A is F cos40, ( angle can be calculated by geometry as 40° )
Hence N2A = F cos 40 = ( WA + WB ) sin20 cos40 = 3144 N
Normal force between spheres is due to the force component WA sin20
Hence Normal force between spheres is resolved component of WA sin20 along the normal
passing through point of contact of spheres.
Hence Normal force between spheres is (WA sin20 cos20) = 964 N
Answered by Thiyagarajan K | 02 Sep, 2019, 11:08: AM
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