FIND

Asked by  | 18th Jun, 2009, 04:31: AM

Expert Answer:

x2 + y2 = 4 (x + y -2)

x2 + y2 = 4x + 4y -8

x2 - 4x + 4 + y- 4y +4 = 0

(x - 2)2 + (y  - 2)2 = 0

(x - 2)2 = - (y  - 2)2 

(x - 2) = ±(y -2)i

Now this won't yield a real value.

Please resubmit the query description with care.

Regards,

Team,

TopperLearning.

Answered by  | 17th Aug, 2009, 08:32: PM

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