Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 12-science Answered

  find the sum of the following series: S = 7/6 + 13/12 + 21/20 +31/30 +............. + 9901/9900 A) 9749/100 B) 9849/100 C) 9949/100 D) 9649/100
Asked by Ranjeetgupta26068 | 12 May, 2019, 01:04: AM
answered-by-expert Expert Answer
if space we space see space the space denominators comma
6 equals 2 cross times 3
13 equals 3 cross times 4
20 equals 4 cross times 5
and space numerators space are
7 equals 2 cross times 3 plus 1
13 equals 3 cross times 4 plus 1
21 equals 4 cross times 5 plus 1
so space it space is space of space the space form
space straight a subscript straight n equals fraction numerator open parentheses straight n plus 1 close parentheses open parentheses straight n plus 2 close parentheses plus 1 over denominator open parentheses straight n plus 1 close parentheses open parentheses straight n plus 2 close parentheses end fraction
straight a subscript straight n equals open parentheses 1 plus fraction numerator 1 over denominator open parentheses open parentheses straight n plus 1 close parentheses open parentheses straight n plus 2 close parentheses close parentheses end fraction close parentheses
straight a subscript straight n equals open parentheses 1 plus fraction numerator straight n plus 2 minus open parentheses straight n plus 1 close parentheses over denominator open parentheses open parentheses straight n plus 1 close parentheses open parentheses straight n plus 2 close parentheses close parentheses end fraction close parentheses
straight a subscript straight n equals open parentheses 1 plus fraction numerator 1 over denominator straight n plus 1 end fraction minus fraction numerator 1 over denominator straight n plus 2 end fraction close parentheses
finding space number space of space terms
1 plus fraction numerator 1 over denominator open parentheses open parentheses straight n plus 1 close parentheses open parentheses straight n plus 2 close parentheses close parentheses end fraction equals 9901 over 9900
straight n equals 98
sum from straight n equals 1 to 98 of open parentheses 1 plus fraction numerator 1 over denominator straight n plus 1 end fraction minus fraction numerator 1 over denominator straight n plus 2 end fraction close parentheses equals 98 plus open parentheses 1 half minus 1 third plus 1 third minus 1 fourth plus...... plus 1 over 99 minus 1 over 100 close parentheses
equals 98 plus open parentheses 1 half minus 1 over 100 close parentheses equals 9849 over 100
Answered by Arun | 13 May, 2019, 09:57: AM
CBSE 12-science - Maths
Asked by suman0987tewary | 27 Feb, 2024, 03:40: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by hemanthpakkela | 24 Feb, 2024, 04:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
t
question image
Asked by rahulkumarphysics1 | 20 Feb, 2024, 09:22: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by sneha47619 | 05 Feb, 2024, 05:24: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by jhaprabhat920 | 05 Feb, 2024, 10:33: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by kreetisinghktt | 04 Feb, 2024, 07:50: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by srisrinivasa.mcrl | 04 Feb, 2024, 10:39: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by raunakumar9300 | 01 Feb, 2024, 04:23: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by shubh31122006 | 01 Feb, 2024, 09:06: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×