find the differentiation

Asked by kumarshee | 20th Mar, 2012, 08:10: PM

Expert Answer:

Put costheta = (1- tan2theta/2 )/(1 + tan2theta/2)
So on solving we get sin-1 [ {(a+b) - (b-a)tan2theta/2}/{(a+b) + (b-a)tan2theta/2}]
which is pie/2 - 2tan-1[root(b-a)tantheta/2]
so we can easily find dy/dx = -root(b-a).sec2(theta/2) / ( 1 + (b-a)tan2theta/2 )

Answered by  | 21st Mar, 2012, 09:11: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.