Find integral of

Asked by joshichaahat | 30th Aug, 2020, 05:41: PM

Expert Answer:

TO find the antiderivative of sqrt{x}+1/sqrt{x}
integral open parentheses square root of straight x plus fraction numerator 1 over denominator square root of straight x end fraction close parentheses dx equals fraction numerator straight x to the power of begin display style 1 half end style plus 1 end exponent over denominator begin display style 1 half end style plus 1 end fraction plus fraction numerator straight x to the power of negative begin display style 1 half end style plus 1 end exponent over denominator negative begin display style 1 half end style plus 1 end fraction equals fraction numerator straight x to the power of begin display style 3 over 2 end style end exponent over denominator begin display style 3 over 2 end style end fraction plus fraction numerator straight x to the power of begin display style 1 half end style end exponent over denominator begin display style 1 half end style end fraction equals 2 over 3 straight x to the power of 3 over 2 end exponent plus 2 straight x to the power of 1 half end exponent

Answered by Renu Varma | 31st Aug, 2020, 12:37: PM