CBSE Class 10 Answered
find all the values of p and q so that 1 , -2 are the zeroes of the polynomial ![x cubed space plus space 10 x squared plus space p x plus q](https://static.topperlearning.com/public/wiris/ckeditor4/plugins/ckeditor_wiris/integration/showimage.php?formula=9f3b56d04748ffa73439e2c94674c9ae)
Asked by sunithapaul2005 | 08 May, 2020, 15:11: PM
p(x)= x3 + 10x2 + px + q
Since -1 and 2 are the zeroes of p(x) then
p(-1) and p(2) = 0
p(-1)= (-1)3 + 10(-1)2 + p(-1) + q = 0
→ -1 + 10 - p + q = 0
→ p - q = 9
→ q = p - 9... (1)
p(2) = (2)3 + 10(2)2 + p(2) + q= 0
→ 8 + 40 + 2p + q = 0
→ 2p + q = - 48
→ 2p + p - 9 = - 48 ...from (1)
→ 3p = -39
→ p = -13
From (1), q = -13 - 9 = -22
Answered by Yasmeen Khan | 08 May, 2020, 20:23: PM
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