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find all the values of p and q so that 1 , -2  are the zeroes of the polynomial Asked by sunithapaul2005 | 08 May, 2020, 03:11: PM Expert Answer
p(x)= x3 + 10x2 + px + q

Since -1 and 2 are the zeroes of p(x) then

p(-1) and p(2) = 0

p(-1)=  (-1)3 + 10(-1)2 + p(-1) + q = 0
→ -1 + 10 - p + q = 0
→  p - q = 9
→  q = p - 9... (1)

p(2) = (2)3 + 10(2)2 + p(2) + q= 0
→ 8 + 40 + 2p + q = 0
→ 2p + q = - 48
→ 2p + p - 9 = - 48 ...from (1)
→ 3p = -39
→   p = -13

From (1), q = -13 - 9 = -22

Answered by Yasmeen Khan | 08 May, 2020, 08:23: PM

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