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evulate double integration
question image
Asked by avusulaprashanti | 01 Feb, 2024, 03:40: PM
answered-by-expert Expert Answer

img

Above itegration can be performed in polar coordinates ( r , img ) over a circular region of radius R and centered at origin.

y = r sinimg

area element  ( dx dy ) = ( dr r dimg)

Hence integration img becomes

img

Above integration vanishes because sine function is integrated from 0 to 2π .

Hence , we get

img

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img

img

img

img

Integration of cosine function over a range from 0 to 2π vanishes

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