Draw a line segment XY of any length and then draw its perpendicular bisector.
Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM
1. Draw a line XY of any length.
2. Taking X as a centre and radius more than half of length XY, draw two arcs in upper and lower portion of XY.
3. Taking Y as a centre and same radius, draw two arcs which cut the previous arcs at E and F.
4. Join EF.
5. Thus EF is the required perpendicular bisector of XY.
Answered by | 4th Jun, 2014, 03:23: PM
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