Draw a circle of any radius and a chord AB in it. Construct a perpendicular from centre to the chord. Does this perpendicular divide the chord in equal parts?

Asked by Topperlearning User | 11th Dec, 2013, 09:47: AM

Expert Answer:

1. Draw a circle with centre O and any radius and make a chord AB.

2. Taking O as a centre and a suitable radius, draw an arc which cut the chord AB at two points X and Y.

3. Taking X and Y as centre and same radius draw two arcs and let them intersect at C.

4. Join OC; name the point of intersection of AB and OC as P.

Measure AP and PB, we find that AP = PB.
Hence, the perpendicular from centre divides the chord in two equal parts.

Answered by  | 11th Dec, 2013, 11:47: AM