Draw a circle of any radius and a chord AB in it. Construct a perpendicular from centre to the chord. Does this perpendicular divide the chord in equal parts?
Asked by Topperlearning User | 11th Dec, 2013, 09:47: AM
1. Draw a circle with centre O and any radius and make a chord AB.
2. Taking O as a centre and a suitable radius, draw an arc which cut the chord AB at two points X and Y.
3. Taking X and Y as centre and same radius draw two arcs and let them intersect at C.
4. Join OC; name the point of intersection of AB and OC as P.
Measure AP and PB, we find that AP = PB.
Hence, the perpendicular from centre divides the chord in two equal parts.
Answered by | 11th Dec, 2013, 11:47: AM
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