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Asked by aryankushagra13 | 25 Mar, 2024, 06:46: AM

if focal length of objective lens is 40 cm , then lens-to-image distance vo of image fromed from an object that is at a distance 200 cm from objective lens is calculated from lens equation

In above equation v = vo ,  u = -200 cm and f = 40 vm

Image formed by objective lens is object of eyepiece.

Let ue is the lens-to-object distance of eyepiece. We want lens-to-image distance of eyepiece as D = 25 cm ( least distance of distinct vision ).

Hence we get from lens equation as

where fe is focal length of eye piece lens .

Hence ue = -3.45 cm

Distance d between objective lens and eyepiece is

d = | vo | + | ue | = ( 50 + 3.45 ) cm = 53.45 cm

( we can consider the round-off distance as 54 cm )

Answered by Thiyagarajan K | 25 Mar, 2024, 12:17: PM
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