CBSE Class 10 Answered
doubt
Asked by akhileshnarayanan | 19 Feb, 2010, 09:08: PM
Expert Answer
Dear Student
Here teh problem is to find the area of the region (circle-triangle)
side if the triangle= 2 r cos 30 = r sqrt 3 = 32 X sqrt3
Area of (circle-triangle)= pi r^2 - r^2 (sqrt3)/4 =r^2(pi-(sqrt3)/4) =32^2 X 2.709= 2774 sq cm
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