CBSE Class 9 Answered
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Asked by srianshgaming09 | 13 Nov, 2023, 09:02: AM
Given equation is
![begin mathsize 14px style left parenthesis 1 minus space a squared right parenthesis space sin theta space equals space left parenthesis 1 plus a squared right parenthesis space cos theta end style](https://images.topperlearning.com/topper/tinymce/cache/da49139fbe864cfeda31443524d43c94.png)
Hence we get , ![begin mathsize 14px style tan space theta space equals space fraction numerator 1 plus a squared over denominator 1 minus a squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/dbc556969c6c719a64312311287e5483.png)
![begin mathsize 14px style tan space theta space equals space fraction numerator 1 plus a squared over denominator 1 minus a squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/dbc556969c6c719a64312311287e5483.png)
Geometrically we get tanθ as shown in figure below
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/f9c3df7f5cf4b21b06eb17c15af532546551abc876cec2.18125423f1.png)
Hence , we get sinθ as
![begin mathsize 14px style sin theta space equals space fraction numerator 1 plus a squared over denominator square root of 2 left parenthesis 1 plus a to the power of 4 right parenthesis end root end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/8763ec66483e163a6e1ceb1fbbfcca24.png)
Answered by Thiyagarajan K | 13 Nov, 2023, 10:29: AM
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