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CBSE Class 9 Answered

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Asked by srianshgaming09 | 13 Nov, 2023, 09:02: AM
answered-by-expert Expert Answer
Given equation is
 
begin mathsize 14px style left parenthesis 1 minus space a squared right parenthesis space sin theta space equals space left parenthesis 1 plus a squared right parenthesis space cos theta end style
 
Hence we get , begin mathsize 14px style tan space theta space equals space fraction numerator 1 plus a squared over denominator 1 minus a squared end fraction end style
Geometrically we get tanθ as shown in figure below
 
Hence , we get sinθ as
 
begin mathsize 14px style sin theta space equals space fraction numerator 1 plus a squared over denominator square root of 2 left parenthesis 1 plus a to the power of 4 right parenthesis end root end fraction end style
Answered by Thiyagarajan K | 13 Nov, 2023, 10:29: AM
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