CBSE Class 9 Answered
Diagonal AC of a parallelogram bisects A. Show that:
(i) it
bisects C also
(ii)
ABCD is a rhombus
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
(i) 1 = 2 (given)
But 1 = 4, 2 = 3 (alt. int. angles)
3 = 4
AC bisects C
(ii) Now, 1 = 4, 2 = 3 (alt. int. angles)
AC = AC (Common)
(by ASA rule)
BC = DC (cpct)
But, AB = DC [Given] AB = BC = CD = AD
Hence, ABCD is a rhombus.
Answered by | 04 Jun, 2014, 03:23: PM
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