determine the AP whose fourth term is 18 and the difference of ninth term from the fifteenth term is 30. plz explain with statement.

Asked by Rutuja Mehta | 18th Jan, 2014, 07:30: PM

Expert Answer:

It is given that 4th term is 18.

a4= 18

a + 3d = 18

a = 18 - 3d            ... (1)

Also, a15- a9= a+14d - 1 - 8d = 30

6d = 30

d = 5

Thus, from (1), we get,

a = 18 - 15 = 3

 

Therefore, the AP is:

3,8,13,18,23 ......

Answered by  | 19th Jan, 2014, 12:12: AM

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