determine the AP whose fourth term is 18 and the difference of ninth term from the fifteenth term is 30. plz explain with statement.
Asked by Rutuja Mehta
| 18th Jan, 2014,
07:30: PM
Expert Answer:
It is given that 4th term is 18.
a4= 18
a + 3d = 18
a = 18 - 3d ... (1)
Also, a15- a9= a+14d - 1 - 8d = 30
6d = 30
d = 5
Thus, from (1), we get,
a = 18 - 15 = 3
Therefore, the AP is:
3,8,13,18,23 ......
Answered by
| 19th Jan, 2014,
12:12: AM
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