Determine mean and standard deviation of first n terms of an A.P. whose first
term is a and common difference is d.

Asked by prakharagarwal1405 | 25th May, 2014, 04:15: PM

Expert Answer:

T h e space g i v e n space A P space b e  a comma space a space plus space d comma space a space plus space 2 d comma space a space plus space 3 d space........... space a space plus open parentheses space n minus 1 close parentheses d space  T h e space g e n e r a l space t e r m space i s space a subscript n equals a space plus space open parentheses n minus 1 close parentheses d  M e a n space equals space mu space equals space fraction numerator a plus space a space plus space d plus space a space plus space 2 d space plus space a space plus space 3 d space........... space a space plus open parentheses space n minus 1 close parentheses d over denominator n end fraction  S tandard space deviation space equals space square root of 1 over n sum from i equals 1 to n of open square brackets a subscript n space minus mu close square brackets squared end root

Answered by Avinash Soni | 27th May, 2014, 11:47: AM