define the refractive index of benzene if the critical angle of it is 42

Asked by ratnamaddala88 | 18th Oct, 2021, 08:18: AM

Expert Answer:

Critical angle, c  = 42°
Let the rafrcative index of benzene be nb 
 
c = sin-1 (1/nb)
42°= sin-1 (1/nb)
sin 42° = 1/nb 
nb = 1/0.67 = 1.49 
Thus, refractive index of benzene is 1.49 

Answered by Shiwani Sawant | 18th Oct, 2021, 02:30: PM