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define the refractive index of benzene if the critical angle of it is 42
Asked by ratnamaddala88 | 18 Oct, 2021, 08:18: AM
answered-by-expert Expert Answer
Critical angle, c  = 42°
Let the rafrcative index of benzene be nb 
 
c = sin-1 (1/nb)
42°= sin-1 (1/nb)
sin 42° = 1/nb 
nb = 1/0.67 = 1.49 
Thus, refractive index of benzene is 1.49 
Answered by Shiwani Sawant | 18 Oct, 2021, 02:30: PM

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