ICSE Class 10 Answered
Cosec²57°-tan²33°+cos44°Cosec46°-√2cos45°-tan²60°
Solve without using trignometrical tables.
Asked by nidhikhire27 | 06 Jul, 2018, 22:49: PM
![begin mathsize 16px style cosec squared 57 degree minus tan squared 33 degree plus cos 44 degree cosec 46 degree minus square root of 2 cos 45 degree minus tan squared 60 degree
equals cosec squared 57 degree minus left parenthesis sec squared 33 degree minus 1 right parenthesis plus cos 44 degree sec 44 degree minus square root of 2 cross times fraction numerator 1 over denominator square root of 2 end fraction minus open parentheses fraction numerator 1 over denominator square root of 3 end fraction close parentheses squared
equals cosec squared 57 degree minus sec squared 33 degree plus 1 plus cos 44 degree sec 44 degree minus 1 minus 1 third
equals cosec squared 57 degree minus cosec squared 57 degree plus 1 plus cos 44 degree sec 44 degree minus 1 minus 1 third
equals 0 plus 1 plus 1 minus 1 minus 1 third
equals 1 minus 1 third
equals 2 over 3 end style](https://images.topperlearning.com/topper/tinymce/cache/66ddb69e30fd6f468650a7b3c7e35b12.png)
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