cos2sin inverse x=cos(cos inverse(1-2x*x))

Asked by harshita srivastava | 15th Apr, 2013, 08:18: PM

Expert Answer:

Let  2sin inverse x = y
then, x = sin(y/2)
since, cos2A = 1-2sin^2(A)
Hence, cosy = 1-2sin^2(y/2)
cosy = 1-2x^2
Hence, y = cos inverse (1-2x^2)
Also y = 2sin inverse x
Hence, 2sin inverse x = cos inverse (1-2x^2)

Answered by  | 16th Apr, 2013, 05:42: AM

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