CBSE Class 10 Answered
clear my doubt
Asked by veenatripathi | 01 Jun, 2020, 10:18: AM
Expert Answer
Question: If the square of the difference of the zeroes of the quadratic polynomial P(x) = x2+px+45 is equal to 144. Find the value of p.
Solution:
Let a and b be the zeroes of the polynomial P(x)
Using the relation between zeroes and coefficients, we have
a+b=-p and ab=45 ... (i)
It is given that (a-b)2 = 144
Therefore, (a+b)2 - 4ab = 144
(-p)2 - 4(45) = 144 ... From (i)
p2 - 180 = 144
p2 = 324
p = 18 or -18
Hence, the value of p is 18 or -18.
Answered by Renu Varma | 01 Jun, 2020, 10:44: AM
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