Asked by khushal305 | 3rd Oct, 2009, 08:36: PM
Given: ABC is isosceles with AB = AC
To prove: Tangent at point A is parallel to BC
Proof: Let the circum circle have its centre at O.
Then by using the theorem, straight line from the centre bisects the chord at right angle.
⇒ OMB = 900
Also, tangent from the point A would be perpendicular to the straight line passing from the centre.
⇒ OAP = 900
SInce alternate angles OMC and OAP are equal.
So, AP || BC
Answered by | 6th Oct, 2009, 03:01: PM
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