Asked by khushal305 | 3rd Oct, 2009, 08:36: PM

Expert Answer:

Given: ABC is isosceles with AB = AC

To prove: Tangent at point A is parallel to BC


Proof: Let the circum circle have its centre at O.

Then by using the theorem, straight line from the centre bisects the chord at right angle.

OMB = 900

Also, tangent from the point A would be perpendicular to the straight line passing from the centre.

OAP = 900

SInce alternate angles  OMC and OAP are equal.

So, AP || BC

Answered by  | 6th Oct, 2009, 03:01: PM

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