ch coplementary angles

show that tan(45+A) tan(45-A)=1

Asked by v.venkateshalu | 17th Nov, 2020, 12:02: PM

Expert Answer:

LHS

= tan(45+A) tan(45-A)

= tan(45+A) tan[90-(45+A)]

= tan(45+A) cot(45+A)

= 1 

= RHS

Answered by  | 18th Nov, 2020, 12:12: PM