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sec of any angle A is
sec A
sec (90˚ − A)
sin A
cosec (90˚ − A)
sec A = cosec (90˚ − A)
sin 2A = √3 sinA for the value of A
30˚
45˚
60˚
90˚
Consider A = 30˚; hence, 2A = 60˚ sin 2A = sin 60˚ = … (i)
… (ii) From (i) and (ii),
sin 2A = √3 sinA for A = 30˚
sec 43˚ + cosec 47˚ is
2sec 43˚
2cosec 47˚
1
Both A and B
sec 43˚ + cosec 47˚ = sec 43˚ + cosec (90˚ − 43˚)
= sec 43˚ + sec 43˚ = 2sec 43˚
sec 43˚ + cosec 47˚ = sec (90˚ − 47˚) + cosec 47˚ = cosec 47˚ + cosec 47˚ = 2cosec 47˚
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