Can you tell the answer for the 23rd question..

Asked by subbukum | 12th Feb, 2020, 05:52: PM

Expert Answer:

(1 + cotθ - cosecθ)(1 + tanθ + secθ)
begin mathsize 16px style equals open parentheses 1 plus fraction numerator cosθ over denominator sin straight theta end fraction minus fraction numerator 1 over denominator sin straight theta end fraction close parentheses open parentheses 1 plus sinθ over cosθ plus 1 over cosθ close parentheses
equals open parentheses fraction numerator sin straight theta plus cosθ minus 1 over denominator sinθ end fraction close parentheses open parentheses fraction numerator sinθ plus cosθ plus 1 over denominator cosθ end fraction close parentheses
equals space 1 over sinθcosθ open square brackets open parentheses sinθ plus cosθ close parentheses squared space minus space 1 close square brackets space space space space space space space space space.... space left parenthesis straight a space minus straight b right parenthesis left parenthesis straight a plus straight b right parenthesis space equals space straight a to the power of 2 to the power of space space end exponent minus space straight b squared
equals space 1 over sinθcosθ open parentheses sin squared straight theta space plus space cos squared straight theta space plus space 2 sinθcosθ minus space 1 close parentheses space space space space space.... space left parenthesis straight a plus straight b right parenthesis squared space equals space straight a squared space plus space straight b squared to the power of space space end exponent plus space 2 ab
equals 1 over sinθcosθ cross times 2 sinθcosθ space space space space space..... space sin squared straight theta space plus space cos squared straight theta space equals space 1
equals 2
end style
Correct Option: B 

Answered by Yasmeen Khan | 12th Feb, 2020, 06:24: PM