can u solve this please.....

Asked by  | 10th Mar, 2009, 08:08: PM

Expert Answer:

(i) (28-8) = (32-12) =20

So the smallest number which leaves remainders 8 and 12 when divided by 28 and 32 is

LCM(28,32) - 20 = 224-20 = 204

 Please raise II question in a separate query

Answered by  | 12th Mar, 2009, 08:53: PM

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