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Calculate the Ryderburg constant R if He+ ions are known to have the wavelength difference between the first (of the longest wavelength)lines of Balmer and Lyman series equal to 133.7 nm..Sir plz do calculations visible to me also..thanks
Asked by vishakhachandan026 | 19 May, 2019, 21:04: PM
answered-by-expert Expert Answer
Wave length of the first line of Balmer series
1 over straight lambda subscript 1 equals RZ squared left parenthesis 1 over 2 squared minus 1 over 3 squared right parenthesis straight lambda subscript 1 equals fraction numerator 9 over denominator 5 straight R end fraction wave space length space of space the space first space line space of space lymen space series minus 1 over straight lambda subscript 2 equals RZ squared left parenthesis 1 over 1 squared minus 1 over 2 squared right parenthesis space straight lambda subscript 2 equals fraction numerator 1 over denominator 3 straight R end fraction triangle straight lambda equals straight lambda subscript 1 minus space straight lambda subscript 2 space space space space space space equals fraction numerator begin display style 9 end style over denominator begin display style 5 straight R end style end fraction minus fraction numerator begin display style 1 end style over denominator begin display style 3 straight R end style end fraction space space space space space space space equals fraction numerator 27 minus 5 over denominator 15 straight R end fraction space space space space space space space space equals fraction numerator 22 over denominator 15 straight R end fraction straight R equals fraction numerator 22 over denominator 15 cross times 133.7 cross times 10 to the power of negative 9 end exponent end fraction space space space equals 1.095 cross times 10 to the power of 7 space space straight m to the power of negative 1 end exponent space space space space space space space space
Answered by Ravi | 20 May, 2019, 14:55: PM
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