ICSE Class 8 Answered
At a certain rate of simple interest 1600 becomes 2200 in 9/2 years .What sum of money will become 5025 in 19/4 at the same rate of interest
Asked by Misra2018dipanko | 19 Nov, 2018, 19:56: PM
Principle P = Rs. 1600, period n = 9/2 years, Amount A = Rs2200
Interest = Amount - Principle = 2200 - 1600 = 600
Interest = PnR/100 = 1600×(9/2)×(R/100) = 600 hence R = (25/3) %
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For second part, n = 19/4 year, Amount = Rs. 5025
P + PnR/100 = P [1+ ( nR/100 ) ] = P { 1 + [ (19/4)×(25/3)/100 ] } = 5025
Solving the above equation for P, we get P = Rs. 3600
Answered by Thiyagarajan K | 19 Nov, 2018, 21:57: PM
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