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Asked by sunnyk67422 | 08 Feb, 2024, 07:11: AM

If the block starts from rest and sliding along the inclined plane ,

then the distance d moved by block at time t is

d = (1/2) a t2

Let us divide time interval of 1 s time dur ation  .

Distance dn moved after n seconds is ,  dn = (1/2) a n2

Distance dn-1 moved after (n-1) seconds is ,  dn-1 = (1/2) a (n-1)2

Distance dn-2 moved after (n-2) seconds is ,  dn-2 = (1/2) a (n-2)2

Let Sn be the time travelled between (n-1) s and (n+1) s

Sn = ( dn - dn-1 ) = (1/2) a [ n2 - (n-1)2 ] = (1/2) a [ 2n-1 ]

Let Sn-1 be the time travelled between (n-2) s and (n-1) s

Sn-1 = ( dn-1 - dn-2 ) = (1/2) a [ (n-1)2 - (n-2)2 ] = (1/2) a [ 2n-3 ]

Answered by Thiyagarajan K | 08 Feb, 2024, 04:55: PM
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